2x^2-3x/20x^2-5x

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Solution for 2x^2-3x/20x^2-5x equation: 


x in (-oo:+oo)

2*x^2-(((3*x)/20)*x^2)-(5*x) = 0

(-3/20)*x^3+2*x^2-5*x = 0

2*x^2-3/20*x^3-5*x = 0

x*(2*x-3/20*x^2-5) = 0

2*x-3/20*x^2-5 = 0

DELTA = 2^2-(-5*(-3/20)*4)

DELTA = 1

DELTA > 0

x = (1^(1/2)-2)/(-3/20*2) or x = (-1^(1/2)-2)/(-3/20*2)

x = 10/3 or x = 10

x = 0

x = 0

x in { 10/3, 10, 0 }

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